Pembahasan Soal Matematika UN SMA/SMK – Fungsi Kuadrat #1

Video tutorial berikut membahas penyelesaian Soal UN 2000 dari Bab Fungsi Kuadrat.

Absis titik balik fungsi \displaystyle y=p{{x}^{2}}+\left( p-3 \right)x+2 adalah p. Nilai p = ….

A. -3

B. \displaystyle -\frac{3}{2}

C. -1

D. \displaystyle \frac{2}{3}

E. 3

(UN 2000)

Ingat koordinat titik puncak fungsi kuadrat adalah \displaystyle P\left( -\frac{b}{2a},-\frac{D}{4a} \right) dengan \displaystyle D={{b}^{2}}-4ac.

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